PHP - Php Code Help Need To Hide A Textarea After Clicking A Button
I have a php form in which ,on click of a edit button the contents of that table row will be displayed in a text area (which appears on the click of that edit button).Below the textarear i have a submit and delete button,i can perform any action.Ater performing the save or delete click the text area should be hidden.
this is not happening,tried with js also. pasting the code below Code: [Select] <form name='add_title' method='post' action=''><?php echo "<br><br>"; if(isset($_POST['update'])) { if(isset($_GET['id'])) { $id = $_GET['id']; $comments=$_POST['comment']; $query1 = "update comments set comments='$comments' WHERE id = '$id' "; $result = mysql_query($query1); //$row=mysql_fetch_row($result); } } if(isset($_POST['delete'])) { if(isset($_GET['id'])) { $id = $_GET['id']; $comments=$_POST['comment']; $query1 = "delete from comments WHERE id = '$id' "; $result = mysql_query($query1); } } $query="select count(*) from comments"; $result =mysql_query($query); $row=mysql_fetch_row($result); $count= $row[0]; if($count!=0) { $query="select *from comments order by id desc"; $result=mysql_query($query); echo "<table width='700' align='center' border=1><tr bgcolor='green' align='center'><td><font color='black'> SlNo </font></td><td><font color='black'>Comment</font></td><td><font color='black'> Date Posted </font></td><td>Edit/Delete</td></tr></b>"; while($row = mysql_fetch_row($result)) { $d=$row['0']; $id=$row['0']; $name=$row['1']; $date_uploaded=$row['3']; echo "<td>$id</td><td>$name</td>". "<td>$date_uploaded</td>". "<td><a href='edit_comments.php?id=$id'>Edit </a></td>". "</tr>"; } if(isset($_GET['id'])) { $id = $_GET['id']; $query = "SELECT comments FROM comments WHERE id = '$id' "; $result = mysql_query($query); $row=mysql_fetch_row($result); echo"<center><table width='700' border='1'><tr><td > <textarea name='comment' cols='80' rows='10'>$row[0]</textarea> <td></tr><tr><td><a href='edit_comments.php?id=$id'><input type='submit' name='update' id='update' value='Save'></a><a href='edit_comments.php?id=$id'><input type='submit' name='delete' id='delete' value='Delete'></a> </td><td></td></center>"; } echo "</table>"; } else { echo "<table width='700' align='center'><tr bgcolor='white' align='center'><td><font color='red' size=2>No comments for you.</font></td></tr></table>"; } ?> Edit: Please use [code][/code] tags when posting code. Similar TutorialsIm displaying the results of a database by using a while loop... so Im trying to figure out how to delete some entries from the datbase. What I wanted to do is add a button in each result that will have the value "delete"... but I cant figure out how to do this. Im kinda new to mysql. I just want it so when I click the button the result will get deleted from the database. I did some research on this but I cant really grasp the examples. Can anybody help me out with this one? Thanks! So, I just don't know where to post this question. I've written a quiz program where 50 English vocab words are pulled from a dB and displayed on one page with the order scrambled. My students then type the Spanish translation for each. When they submit the form the next page grades their work. They have to get a 90 or better for the grade to be automatically recorded, so I want them to click the back button and go back and make corrections. The problem is when they use a Chrome browser and click the back button the program re-sorts the order of questions. It leaves the order of their answers the same. So what they answered for number 1 is still in the field for number 1, but the questions (the English vocab word) is different. Chrome does this consistently so I thought this was a Chrome issue only. Then one of my students said the same thing happened to her when using Safari. So here is my question, how can I stop Chrome (or any other browser) from re-running my server-side PHP scripts (re-sorting the vocab array) when clicking the back button?
Here is the code for students taking the quiz:
<form method="post" action="portal.php?load=vquiz_grade" style="margin-left: 50px; line-height: 30px;">
$max = $count-1;
?>
//print "<br>";
<input type="hidden" name="max" value="<?print $max?>"> And here is the code showing them what they missed.
<?
// Total grade
print "You missed ".$wcount." words.<br>";
print "<table>";
// Grade response and set color
if ($wrong == 1){ if ($grade >= 90){
$query = "SELECT * FROM inno_vocab_assignments WHERE key_code = '$key_code' AND uname = '$secure_uname' AND teacher = '$teacher'";
// Prevent student from changing vocab list so as to do an easier list
// Insert grade
}
Thank you!
Hi i am working one of my assignment for school.. i just studied php.. my problem is, is it possible to load another form once i clicked a radio button? if its a yes... can you teach me how to do that? thank you! Folks,
Look at this weird thing. I load the page and get echoed as expected: Did Not REQUEST_METHOD! Then, I click the SUBMIT button and to my astonishment I get echoed: Did Not POST->Submit! Got 2 buttons. Same result whenever clicking any. Why is that ? Check it out:
<?php //include('error_reporting.php'); ini_set('error_reporting',E_ALL);//Same as: error_reporting(E_ALL); ini_set('display_errors','1'); ini_set('display_startup_errors','1'); ?> <form name = "submit" method = "POST" action=""> <label for="domain">Domain:</label> <input type="text" name="domain" id="domain" placeholder="Input Domain"> <br> <label for="domain_email">Domain Email:</label> <input type="email" name="domain_email" id="domain_email" placeholder="Input Domain Email"> <br> <label for="url">Url:</label> <input type="url" name="url" id="url" placeholder="Input Url"> <br> <label for="link_anchor_text">Link Anchor Text:</label> <input type="text" name="link_anchor_text" id="link_anchor_text" placeholder="Input Link Anchor Text"> <br> <textarea rows="10" cols="20">Page Description</textarea> <br> <label for="keywords">Keywords:</label> <input type="text" name="keywords" id="keywords" placeholder="Input Keywords related to Page"> <br> <input type="checkbox" name="alert_visitor_type" id="alert_visitor_type" value="Give Alert: Visitor Type"> </label for="alert_visitor_type">Give Alert: Visitor Type</lablel> <input type="checkbox" name="alert_visitor_potential" id="alert_visitor_potential" value="Give Alert: Potential Visitor"> </label for="alert_visitor_potential">Give Alert: Potential Visitor</lablel> <br> <input type="radio" name="tos_agree" id="tos_agree_yes" value="yes"> <label for="tos_agree_yes">Yes:</label> <input type="radio" name="tos_agree" id="tos_agree_no" value="no"> <label for="tos_agree_no">No:</label> <br> <label for="tos_agreement">Agree to TOS or not ?</label> <select name="tos_agreement" id="tos_agreement"> <option value="yes">Yes</option> <option value="no">No</option> </select> <br> <button type="submit" value="submit">Submit</button><br> <button type="submit">Submit</button> <br> <input type="reset"> <br> </form> <?php if($_SERVER['REQUEST_METHOD'] === 'POST') { if(isset($_POST['submit'])) { mysqli_report(MYSQLI_REPORT_ALL|MYSQLI_REPORT_STRICT); mysqli_connect("localhost","root","","test"); $conn->set_charset("utf8mb4"); $query = "INSERT into links (domain,domain_email,url,link_anchor_text,page_description,keywords,alert_visitor_type,alert_visitor_potential) VALUES (?,?,?,?,?,?,?,?)"; $stmt = mysqli_stmt_init($conn); if(mysqli_stmt_prepare($stmt,$query)) { mysqli_stmt_bind_param($stmt,'ssssssss',$_POST['domain'],$_POST['domain_email'],$_POST['url'],$_POST['link_anchor_text'],$_POST['page_description'],$_POST['keywords'],$_POST['alert_visitor_type'],$_POST['alert_visitor_potential']); if(mysqli_stmt_execute($stmt) === FALSE) { die("Error\" . mysqli_stmt_error()"); } mysqli_stmt_close($stmt); mysqli_close($conn); } else { die("Did not INSERT!"); } } else { die("Did Not POST->Submit!"); } } else { die("Did Not REQUEST_METHOD!"); } ?>
So I am trying to execute an sql query by clicking a button or a link. Ultimately I want users to be able to click the "Fav" button and it then fades into "Added to favorites!" (I am building a favorite system which first collects data on page load like userid and itemid and then it needs to send it to the DB after a button is clicked) The fade and stuff is not the most important part now (although a tip on doing that would be awesome) but the most important part is how to get this functional: PHP Code: <?php // Start Favorite System! $user =& JFactory::getUser(); $userid = $user->id; if ($userid == 62) { echo "userID: ".$userid."<p />"; if ($user->guest) {echo "You are a guest<p />";} $itemid = $this->item->id; echo "itemID: ".$itemid."<p />"; $catid= $this->item->category->id; echo "catID: ".$catid."<p />"; $query = "INSERT INTO jos_k2_fav_xref (userID, itemID, catID) VALUES ('$userid', '$itemid', '$catid')"; // Need a way to make this into a button $run = mysql_query($query) or die(mysql_error()); } else {} ?> Currently all the values get stored in the DB as the page is loaded. I however want to be able to click on something to execute that query how do i do that? I read a bunch of stuff on javascript and ajax but it got me nowhere... Help is greatly appreciated! Dear All I have a form say i have selected Volva from drop down box . So without clicking on submit button when i move to next field that is `<input>` the value that is volva should get store in php variable <html> <body> <form action=""> <select name="cars"> <option value="volvo">Volvo</option> <option value="saab">Saab</option> <option value="fiat">Fiat</option> <option value="audi">Audi</option> </select> <input type="text" name="abc" /> </form> </body> </html> This topic has been moved to JavaScript Help. http://www.phpfreaks.com/forums/index.php?topic=357107.0 This topic has been moved to Ajax Help. http://www.phpfreaks.com/forums/index.php?topic=326913.0 Please, take a look to the following code.After clicking Next it goes to overview.php.Why when I click back on my browser to return to this page again, it is not returning back? When I click back I receive "Confirm Form Resubmission" message. After refreshing page it loads page. I guess problem is in "session_start();" part. Something to do with cookies. Please, help me it is very urgent for me. <?php session_start(); echo "<html> <head> <title>Hello World</title> <meta http-equiv='Content-Type' content='text/html; charset=Windows-1252'/> </head>"; require_once ('functions.inc'); if(!isset($_POST['userid'])) { echo "<script type='text/javascript'>"; echo "window.location = 'index.php'"; echo "</script>"; exit; }else{ session_register("userid", "userpassword"); $username = auth_user($_POST['userid'], $_POST['userpassword']); if(!$username) { $PHP_SELF = $_SERVER['PHP_SELF']; session_unregister("userid"); session_unregister("userpassword"); echo "Authentication failed " . "Please, write correct username or password. " . "try again "; echo "<A HREF=\"index.php\">Login</A><BR>"; exit; } } function auth_user($userid, $userpassword){ global $default_dbname, $user_tablename; $user_tablename = 'user'; $link_id = db_connect($default_dbname); mysql_select_db("d12826", $link_id); $query = "SELECT username FROM $user_tablename WHERE username = '$userid' AND password = '$userpassword'"; $result = mysql_query($query) or die(mysql_error()); if(!mysql_num_rows($result)){ return 0; }else{ $query_data = mysql_fetch_row($result); return $query_data[0]; } } echo "hello"; echo "<form method='POST' name='myform' action='overview.php'>"; echo "<input type='submit' value='Next'>"; echo "</form>"; ?> hey im doing a school project, where i need to limit the menu access to logged in people only. is that even possible? Thanks for you help Hello dear friends, If i've database table (my_table) with one field (text) and i've created form with textarea Code: [Select] <form action="#"> <textarea name="text" id="text"></textarea> <input type="submit" name="Submit" value="Submit"> </form> I can add any text inside it and save it in my database table but when i add html codes it also store it perfect but only 2 codes is not the closing of form and textarea </form> and </textarea> it not stored and automatically not saved Why ! i mean if i paste inside the above form - textarea the following code for example Code: [Select] <form> <textarea>blah</textarea> </form> it will store it as Code: [Select] <form> <textarea>blah and will not store </form> and </textarea> how then i can add html codes with textarea and form inside it without conflict thanks Hi I have a text area, that I want to display info pulled from a database. I can get the data to show, But can get each entry of the table to display on it's own line. Example: ob1ob2ob3ob4ob5 Should be: ob1 ob2 ob3 ob4 ob5 CODE: Code: [Select] <textarea id="interest" onfocus="clearInterest()" class="textareacss" style="height:212px;overflow:auto;"><?PHP $newInterestSub = Admin_interests_sub::find_by_cat_id($id); foreach($newInterestSub as $newInterestSubs){ echo $newInterestSubs->interest_sub.'\n'; } ?></textarea> Any help would be great. hi, I have some HTML to edit in my database, in my back end administration I have it in a textarea but when I go to edit it, it all messes up and lots of '/' area added, see below: Code: [Select] Site Design by: <a href=\\\\\\\"http://www.jbiddulph.com\\\\\\\" target=\\\\\\\"_blank\\\\\\\" title=\\\\\\\"John Biddulph - Web Development\\\\\\\">jbiddulph.com</a> php code Code: [Select] <p> <label>Site Design by</label> <textarea class="text-input small-input" name="SiteDesignby"><?php echo $row1['SiteDesignby'] ?></textarea> </p> someone suggested adding this to my page: SiteDesignby.value = SiteDesignby.value.replace(/\\*."/g,'"'); I added the code and nothing changed! Can anyone help please? I'm having a problem with some php code that allows you to edit a text file. No matter what file it loads, it always adds four horizontal tabs and two spaces to the end of the text. I've attached the code to this post. If anyone can help me with this, it would be greatly appreciated. Cindy So I am completely done with my forum after several posts here and a lot of time. But crap! I just realized that the way my avatar system works it will give away the password! I REALLY don't want to redo that system because truth is it is about 40 percent of the entire sites coding. It works by making pictures in a directory named the usersname.thepassword . Whatever filesystem. Now when I echo the path everyone can see the password and username in the source code! And thy can click it to see the picture! Is there a way to hide the paths or the source codeM thanks! So I am completely done with my forum after several posts here and a lot of time. But crap! I just realized that the way my avatar system works it will give away the password! I REALLY don't want to redo that system because truth is it is about 40 percent of the entire sites coding. It works by making pictures in a directory named the usersname.thepassword . Whatever filesystem. Now when I echo the path everyone can see the password and username in the source code! And thy can click it to see the picture! Is there a way to hide the paths or the source codeM thanks! Hello all, I have a website where I do not want the Javascript to be viewable by the client right-clicking and choosing "View source". I am using specific Google Maps API so it has to be Javascript, there is unfortunately no server side equivalent. Is there a way for me to have a skeleton webpage that sends the data to a severside page -- where the javascript is processed -- then returned somehow back to the client? Forget for a second that I'm using Google Maps, but just looking at it from a higher level view: Is it possible to have a webpage where I submit data -> goes to the server where it's processed using javascript -> then returns HTML to the client? Thanks!! I have a form that generates html code, and displays it in a textarea with submit button. I want to submit button to take the data entered in that textarea1 on page 1, and upload to textarea2 on page 2 How can I do this? I have no idea where to start. Ok my question is, when they hit the "Play!" button, then I want the php code below to pop up. Like... i think I would use the GET method, but I'm not sure still. I don't think that really matters what method you use, but how do I say IF they click on the "Play" button, then lead them to this code so they can start playing the game. I'm entering this into the database, but I'm just trying to get this code first. I already know how to make it lead to the database and whatnot. <?php session_start(); include("logincheck.php"); ?> <?php include_once("header.php"); ?> <br> Welcome to the Six Dice game. <br><br><b>Instructions</b>: You play this game by randomly rolling a dice. If you land on 1-5, you earn 0 rp. If you land on a 6, you earn 500rp! The game is free so why not give it a shot? <br>You may only play this game 25 times a day! <br><br><form action="sixdice.php?roll" method="post"> <input type="submit" name="playsix" value="Play!" /> </form> <?php if(isset($_POST['playsix'])); $dice = rand(1,6); echo "You rolled a<br /><b>{$dice}</b>\n"; $winnings = "500"; if($dice == 6) { include("haha.php"); $cxn = mysqli_connect($dbhost,$dbuser,$dbpassword,$dbdatabase); $username = $cxn->real_escape_string($_SESSION['username']); $sql = "UPDATE `Member` SET `rp` = rp+$winnings WHERE `username` = '$username'"; mysqli_query($cxn,$sql); }?> <FORM ACTION="sixdice.php" METHOD="post"> <INPUT TYPE="submit" VALUE="Roll Again!" /> </FORM> <?php include_once("footer.php"); ?> Hi folks, I try to keep my explanation as short as possible. I have a page that loads a php script on opening with all the cards in my database. When a player clicks a div of a specific card div a popup comes up asking if he wants to add this card to his collection. When choosing yes the specific card goes into his private collection. Problem is, the card div has already got an ID for layout purpose. Can i give this div somekind of extra info while generating them from my PHP script. And then sent that info back to the PHP script that should add the card to the players DB. I am using Jquery to sent and receive data from my php script something like this. Code: [Select] <script> $(document).ready(function(){ $('#halfrow').click(function(){ //<-- the div that gets clicked $('#popuplarge').css({'visibilty':'visible'}) //<-- the popup $.post( "addcard.php", { cardID: $("#cardDiv").val()}, //<--- here i sent the info to the php script so the correct card can be added. function(data) { $("#popuplarge").html(data); }); }); }); </script> Is there a way to add a hidden <input /> with the card ID div and then sent that trough with Jquery? Still the same problem here as all the divs have the same ID and the jquery script would not know witch hidden <input /> to sent. I could also make the whole div a button but thats probably not desirable for layout purpose. I can always add a button to the div wich has to be clicked. But i would really like the user can click anywhere on the div. And i rather not want to redesign the div . |