PHP - Check If Its One Hour Before Time
So I am trying to check if the current time is one hour before a variable time:
Code: [Select] $date_game=$dt->format('Y n j'.$pieces[2]); echo $date_game; echo date('Y n j H'); if (date('Y n j H') < $date_game) { echo "The time is before the stored time"; } This displays 2012 1 21 17:30 2012 1 21 16 i.e $pieces[2] = 17:30. and $dt formatted Y n j = 2012 1 21. The current Y n j H is 2012 1 21 16. I want to know if it is more than one hour until the date/time stored in $date_game. At the moment it just tells me that it is before that time. Can I do something like Code: [Select] $data_game - 1->format('H'); or something? Thanks guys Similar TutorialsI am trying to display date and time below code display date correctly but when it come to display time it display 3 hour behind. eg. when it is 12:47 PM in my system it display 9:47 PM Code: [Select] <?php $todaydate=date("j - F - Y g:i:s a"); echo $todaydate; ?> $time="19:00:00"; how to do i output one hour later from the variable above? My site allows users to vote once per hour, and it checks the next time they vote if it's been 3600 seconds (1 hour) since their last vote. But, it always returns the value 0. $grab = mysql_fetch_assoc($has_voted); $calc = strtotime($grab['date']) - strtotime(date("M-d-Y")); if($calc > 3600) { mysql_query("DELETE FROM votes WHERE ip = '". $_SERVER['REMOTE_ADDR'] ."'"); header("location:votes.php?id=". $id .""); } else { echo echo "You've voted within the last hour. Please wait ". $calc ." seconds."; } I insert a time value using the following code
$ti= ( !empty($_POST['time']) ) ? "'{$_POST['time']}'" : 'NULL';
I want to insert a second time value into a differen column which would be the same time minus 1 hour
something along the lines of :
$ti2= ( !empty($_POST['time']) ) ? "'{$_POST['time'] -1 hour}'" : 'NULL';
What would be the correct way to do it
When I echo the current time, the hour is what it is plus one: echo date("h:i:s:A"); Real time is 3:46:33 Would display 4:46:33 What is wrong here? Could i use curl to check api response time and if so how? I want the script to check if something already has been submitted into the database before the submission, I tried it to do it with num_rows, but I'm encountering a problem. Here's the script: $con_submit = $_POST['submit']; $user_id = $_SESSION['user_id']; if ($con_submit && isset($user_id)) { $dbc = mysqli_connect(DB_HOST, DB_USER, DB_PASSWORD, DB_NAME); // POST variables $knuffix_name = strip_tags(trim($_POST['knuffix_name'])); $knuffix_contribution = $_POST['knuffix_contribution']; $knuffix_category = strip_tags(trim($_POST['sort_category'])); $query = sprintf("SELECT * FROM con WHERE contribution = '%s'", mysqli_real_escape_string($dbc, $knuffix_contribution)); $query_run = mysqli_query ($dbc, $query) or die (mysqli_error ($dbc)); $num_rows = mysqli_num_rows ($query_run) or die (mysqli_error ($dbc)); // $assoc = mysqli_fetch_assoc ($query_run) or die (mysqli_error ($dbc)); echo "num rows" . $num_rows; // and then as an example: if ($num_rows == 0) { // run INSERT INTO script } } When there are entries in the database then num_rows will return me the amount of entries in the echo, BUT if there are ZERO entries, then nothing will happen, and that is because of the query. Since the query looks as follows: Code: [Select] SELECT * FROM con WHERE contribution = '$variable_post_submission' Which means if there's no entry in the database at all, then the query has nothing to select, which again makes the rest of the script NOT work. Which means that num_rows does not return any value, the echo will not even get printed out. But I on the other hand would like num_rows to return zero and have the script continue by INSERTING the submitted data into the database. Any ideas how I could accomplish this? Hello Coders, Iam in a confused situation. I made a php script & in that script i want to check how much time (in seconds) the page is taking to fetch the content from the server. If the time is greater than to i defined time then i want to show a error message to the users. Anybody can give me ideas ..................... ?? Is there a way to run a check on the server to see how long it takes for the page to get built, then print it to the screen?
I tried searching for it online for a few minutes, but it wasn't able to be found. All I'm finding on there is how to optimize the pages, but I want a simple time check performed on the page loading
Hi, i'm trying to create some detailed statistics about customer activity, i have entries in my mysql db when the customer has been active for the last time and want to create some statistics about that, basically a "online last 24 hours" but from specific countries. Now i've tried this: Code: [Select] $time = date('Y-m-d H:i:s'); $time24 = date("Y-m-d H:i:s", time()-((60*60)*24)); $query = "SELECT COUNT(*) as Anzahl FROM customers WHERE country = 'de' AND time BETWEEN '$time' AND '$time24' "; to get the current date and select all customers that have been available from the current date minus 24 hours, what's my mistake here, as this doesn't seem to work! Thanks Hello, I am trying to load an external image from a NOAA site directory. This image refreshes every three hours, starting with 0 and then 3,6,9,12.....21 in a 24 hour calendar, and are stored for days in advance. The date/time is in the file name. Originally I had written the script to refresh on the hour, and then realized the tri-hourly spacing. This is what I have: Code: [Select] <?php date_default_timezone_set('Etc/GMT-1'); $today = date("YmdH"); $pattern = '/WaveHeight_'.$today.'_mic.png'; $base_url = 'http://www.crh.noaa.gov/images/greatlakes/ndfd/MIC/dynamic2'; print '<a href="http://www.crh.noaa.gov/greatlakes/?c=map&l=lm&p=a"><img src="'.$base_url.$pattern.'" width= "237" hieght= "314" " ></a>'; ?> I am not fluent in php, but I assume I need a "If H=1,4,7,10,13,16,19,22; Then H+2 ; along with If H=2,5,8,11,14,17,20,23; Then H+1" to keep the images relatively current. I just can't quite wrap my head around how to express this. Any help is appreciated. Thank you. Hello, I have a very simple table... DAY (Y-m-d) / TIME (00:00:00) / POWER (INT) I am using a Jquery datepicker to select the date on the page, and that POST to the PHP file. I am trying to select values from Mysql to make 3 HighCharts Graphs using the selected day of the datepicker. I have started with the DAY graph PHP to get the values for each hour of a 24 hour day. I need to get the values for each hour... 23,12,15,35 etc... , and then I need for the 31 days of a month for the month graph, and 12 months of the year for the month graph all in the same way so the HighCharts can use the values to make the chart (3 php files, one for each graph) Here is the PHP I have for the 1 day that should get the 24 individual hour data, but it does not seem to work... <?php $choice = (isset($_POST['choice'])) ? date("Y-m-d",strtotime($_POST['choice'])) : date("Y-m-d"); $con = mysql_connect("localhost","root","mackie1604"); if (!$con) { die('Could not connect: ' . mysql_error()); } mysql_select_db("inverters", $con); $sql = "SELECT HOUR(time), COUNT(power) FROM feed WHERE time = '".$choice."' GROUP BY HOUR(time) ORDER BY HOUR(time) "; $res = mysql_query($sql) or die('sql='.$sql."\n".mysql_error()); $row = mysql_fetch_assoc($res); echo $row['choice'].'<br />'; ?> What have a written wrong in the sql query ??? Alan Hi I want to make something like this - My Sites index.php will be avail avail to user after he has clicked in a link that will come after every 24 Hour in my site. Means when a user first enters the site it will come and clicking in there the site will be avail avail. again after 24 Hour it will come again. But i am not getting how to do it. So need help SaKIB Hi guys, I have a PHP Script were user would enter a username and password to get access, but the problem I keep having is every half n hour or so user have to sign in again cause the keeps logging them out for some reason. Please I need your help and advice to make this stop. Hi all, I have a loop that is modifying a DateTime object. It goes through X number of times and adds 1 day to the date time object and stores the modified object in an array. I use ->add(new DateInterval('P1D')); For some reason it is losing an hour each time that I add a day. I start out at 19:00 and each iteration through the loop adds a day, but loses an hour. 2010-09-19 19:00:00 2010-09-20 18:00:00 2010-09-21 17:00:00 I can correct for this by doing ->add(new DateInterval('P1DT1H'));, but adding 25 hours instead of 24 hours doesn't make any sense to me. I am using PHP Version 5.3.1. Any ideas? Thanks, W Hi,
I have a blog which records the amount of views on each article. I now want to be able to work out the average number of views per hour.
How can I work out the number of hours passed from a datetime format?
From there I can just do views divided by hours passed.
Thanks in advance!
This topic has been moved to PHP Freelancing. http://www.phpfreaks.com/forums/index.php?topic=332844.0 Hi, I am creating a date string using the following: $curDate = date("Y-m-d H:i:s"); However, what I want to do is take one hour off this so that $curDate now becomes the current date and time minus one hour. Thanks for your help. Hey guys only thing i can find online is examples of showing how much time is left until a predetermind time. but what I need is how many minutes are left until the next hour hits anyone have any ideas on this? Im wanting to do it in UNIX time Hello, Im trying to work out some code. On my site between Thursday 12th July and Sunday 15th July between the hours of 22:00 and 23:00 I want to display some code. I've done this so far, but am having trouble. Anyone please help? $the_date = date("H:i:s"); $timesep = explode(":",$the_date); // $hour = $timesep[0]; if (($the_date > 2010-08-12 && < 2010-08-15) && ($hour >= 22) && ($hour <= 23)) { //Code } |